2x^2-3x+1=10

Solution for 2x^2-3x+1=10 equation:

Simplifying
2x2 + -3x + 1 = 10

Reorder the terms:
1 + -3x + 2x2 = 10

Solving
1 + -3x + 2x2 = 10

Solving for variable 'x'.

Reorder the terms:
1 + -10 + -3x + 2x2 = 10 + -10

Combine like terms: 1 + -10 = -9
-9 + -3x + 2x2 = 10 + -10

Combine like terms: 10 + -10 = 0
-9 + -3x + 2x2 = 0

Factor a trinomial.
(-3 + -2x)(3 + -1x) = 0

Subproblem 1
Set the factor '(-3 + -2x)' equal to zero and attempt to solve:

Simplifying
-3 + -2x = 0

Solving
-3 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -2x = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2x = 0 + 3
-2x = 0 + 3

Combine like terms: 0 + 3 = 3
-2x = 3

Divide each side by '-2'.
x = -1.5

Simplifying
x = -1.5
Subproblem 2
Set the factor '(3 + -1x)' equal to zero and attempt to solve:

Simplifying
3 + -1x = 0

Solving
3 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x = 0 + -3
-1x = 0 + -3

Combine like terms: 0 + -3 = -3
-1x = -3

Divide each side by '-1'.
x = 3

Simplifying
x = 3
Solution
x = {-1.5, 3}